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#1 May 04, 2009 4:26 AM

cooldude22345
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Math help!

Need help with math? Just post your questions here! But don't try to cheat on your homework. That's a no no.

Also, I'm not really good at math, so I'm kinda hoping that somebody here could help or try to.

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#2 May 04, 2009 4:29 AM

Aicebo
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Re: Math help!

Calculators are your friend.


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#3 May 04, 2009 4:31 AM

cooldude22345
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Re: Math help!

not mine. unless you can figure how to graph equations with them...

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#4 May 04, 2009 4:33 AM

Aicebo
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Re: Math help!

Hahaha, schools these days and the malarky that you'll never need to know later on in life...


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#5 May 04, 2009 4:34 AM

cooldude22345
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Re: Math help!

EXACTLY. when will I use this to fix a car when I'm older??? NEVER.

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#6 May 04, 2009 6:58 AM

bmah
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Re: Math help!

Need help for Pokemon games? Need help in math?

I think people will post their questions on a subject if they actually need help. Given the wide range of topics that can be discussed in terms of homework or game help, a thread to anticipate the help of a specific subject isn't needed.

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#7 May 04, 2009 12:50 PM

Aceedwin
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Re: Math help!

The temptation to challenge you to some kind of "math-off" is almost overwhelming.

Alright, I'm going to go find one of my math challenges. We'll see who can do maths.

Here we go...

"The product of Mary's age in years on her last birthday and her age now in complete months in 1800. How old was Mary on her last birthday?"

A) 9   B) 10   C)12   D) 15   E) 18

If you're any good, that won't be a problem.


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#8 May 04, 2009 2:40 PM

cooldude22345
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Re: Math help!

You guys bug.

I'm really no good at math. I'm getting help for discalculia, but all I really do in this problem is guess.

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#9 May 04, 2009 2:49 PM

Stormy
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Re: Math help!

I'm in calculus now; I should be able to help most of you. Or not. =P

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#10 May 04, 2009 8:10 PM

Swaffy
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Re: Math help!

Yeah, we are going over stuff like ...

2 log 5X^(1/2) = 4
[Something like that.]

[Example]
Solve the equation for X.
log 4X = -1

Steps
4X = 10^(-1)
4X = .1
X = 0.025

There you go ...


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#11 May 04, 2009 11:45 PM

TheAnvil
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Re: Math help!

Ouch! Even that makes my head hurt. I found as soon as I was out of college that all my math skills went on vacation and never came back. Rudimentary math I can do, but that stuff makes me shudder.

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#12 May 05, 2009 9:21 AM

freak6
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Re: Math help!

oh we have stuff around that its really confusing and easy to get lost in i have a tudor for maths and it is my worst enemy i suck at it so bad....


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#13 May 05, 2009 12:20 PM

midget_roxx
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Re: Math help!

Anyone here do discrete maths smile. Might need help with mathematical proofs and  logic statements big_smile.

Swaffy wrote:

Yeah, we are going over stuff like ...

2 log 5X^(1/2) = 4
[Something like that.]

[Example]
Solve the equation for X.
log 4X = -1

Steps
4X = 10^(-1)
4X = .1
X = 0.025

There you go ...

HA! Wait till you get to proper calculus wink. Believe me you'll find logs easy compared to integrals sad. They are the death of your mind

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#14 May 05, 2009 5:00 PM

Stormy
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Re: Math help!

Integrals aren't hard if you just memorize all the formulas, or at least have somewhere to look them up if you forget. Same with derivatives. The hardest part for me is understanding why exactly the rules work the way they do.

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#15 May 06, 2009 6:03 AM

bmah
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Re: Math help!

if you delve further into calculus, integrals becomes your best friend and you use them all the time. Eventually, you can integrate anything. In AP/1st year college calculus, you're pretty restricted with knowing only a limited number of rules and therefore you can only integrate a few things.

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#16 May 06, 2009 8:07 AM

freak6
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Re: Math help!

wow and now everyone is talkign jibberish to me and tlaking abotu stuff i havnt even heard of yet....O__o


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#17 May 06, 2009 6:12 PM

Stormy
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Re: Math help!

bmah wrote:

if you delve further into calculus, integrals becomes your best friend and you use them all the time. Eventually, you can integrate anything. In AP/1st year college calculus, you're pretty restricted with knowing only a limited number of rules and therefore you can only integrate a few things.

Ah, that explains a lot. I thought we were just going to keep learning rules and formulas until we had one to apply to every type of problem. That would be a lot to remember, heh.

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#18 May 06, 2009 7:36 PM

pur
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Re: Math help!

Differentiation? Integration? Logarithms?

OH JOY. I was revising them earlier in a Maths Day trip to Keele University. Along with Indices, Trigonometry, Radians and Sequences.

Logarithms aren't so bad, unless you're like me and forget your calculator. I still can't believe I forgot my calculator. Fortunately, we didn't need it, as we were only going through worked examples.


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#19 May 06, 2009 9:01 PM

Swaffy
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Re: Math help!

True.

We are only going over Natural Logarithms and the other form of
Logarithms right now. It is easy if I take notes. Math has always been my
good subject. History is a bad one, and Spanish is pure failure for me.

When it comes to 30 60 90 triangles, needing to use cosine, tangent, and
sine, I get stuck. That stuff gets me unless I use a calculator.


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#20 May 07, 2009 12:43 AM

dragonmissioner
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Re: Math help!

OK, I am really good at geometry but I stink at word problems.

Here is what I have.

What is the outside diameter (to the nearest meter) of a circular track 6 meters wide if one forth of the inside circumference is 100 meters?

At first glance I thought it gave me diameter or radius. But then I saw 1/4 circumference is 100 meters. Does that mean that the actual circumference is 400 meters?


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#21 May 07, 2009 3:04 AM

Swaffy
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Re: Math help!

Oh, I get it.

Diameter = 6m
Circumference = 100m

There are two circles. Apparently, they didn't give enough information.
Try messing around with using the formulas for the circumference of a
circle.

C = [pi] d


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#22 May 11, 2009 3:53 AM

Cesna
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Re: Math help!

What's 1e+9?  And for that matter, what does the e even mean?


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#23 May 11, 2009 5:45 AM

bmah
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Re: Math help!

I usually think of e as the natural log but in your case it might just be a variable.

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#24 May 11, 2009 1:38 PM

Stormy
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Re: Math help!

e is a constant (like pi) that equals about 2.7. So 1e+9 would be 11.7.

Or it might just be a variable like bmah said.

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#25 May 11, 2009 4:16 PM

Aceedwin
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Re: Math help!

Did you know it's possible to have a square of constant area, but infinite perimeter? Actually, it probably works on any polygon.


It is often said that before you die your life passes before your eyes. It is in fact true. It's called living.

anti_mind_virus.png
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